there are only 2 solutions: 78981/101547 and
79191/101817.-michael marfil

I think your puzzle has the solution…
SEVEN = 78981
NINTHS = 101547
Also, see http://users.aol.com/s6sj7gt/mikealp.htm for 
Mike Keith's alphametics page – taking them to the 
extreme. There are some truly (perhaps maximally) dense 
puzzles there.
Regards
Mark Michell

The first double true of this kind I know was 
by Jesus Sanz and was send to the spanish puzzle 
list Snark some monthes ago, maybe more, was:
Cripto Fraccion 1: (Jesus Sanz)
TRES/OCHO = 3/8
Then I found:
Cripto Fraccion 2:
TRES/NUEVE = 3/9  sin usar el 0.
4562/13686
Cripto Fraccion 3:
CUATRO/VEINTE = 4/20
170469/852345
Cripto Fraccion 4:
CINCO/TRECE = 5/13
30435/79131
Cripto Fraccion 5:
SEIS/DIEZ = 6/10
4914/8190
Cripto Fraccion 6:
SEIS/TRECE = 6/13
6876/14898
Cripto Fraccion 7:
SIETE/TRECE = 7/13
17535/32565
Cripto Fraccion 8:
DIEZ/TRECE = 10/13
9650/12545
Cripto Fraccion 9:
(UNO+SIETE)/CINCO = 8/5
670+54898/34730
Cripto Fraccion 10:
(DOS+NUEVE)/CINCO = 11/5
357+64818/29625
Cripto Fraccion 11:
(TRES+TRECE)/CINCO = 16/5
8473+84727/29125
Cripto Fraccion 12:
(SEIS+QUINCE)/CINCO = 21/5
9389+278563/68560
I also found this kind of problem/solution in English 
but I cannot find now.
My daughter has 1 and 1/2 year, no time for puzzles!
Best wishes,
Rodolfo Kurchan

Dear Sir,
E = 8, H = 4, I = 0, N = 1, S = 7, T = 5, V = 9
SEVEN = 78981
NINTHS = 101547
SEVEN/NINTHS = 78981/101547 = 7/9
Regards,
Veo Chau

Seven   78981
Ninths   101547
Neil Jones

Bryce problem
7/9 = 78981/101547.
Regards
Eswaran Narasimhan

Hi Ed,

I solved Bryce Herdt's proportion:

 SEVEN/NINTHS=7/9
 78981/101547=7/9  or {S=7, E=8, V=9, N=1, I=0, T=5, H=4}

Solution strategy (since I like to see people's methods): 
(1) 7x < 100,000 and 9x >= 100,000  (given number of letters)
(2) 11,111 < x < 14,285  (from 1)
(3) N=1  (since 9x < 128,565  from 2) 
(4) 11,248 < x < 13,555  (since 101,234 < 9x < 121,987  from 3)
(5) S=7 (since 7x ends in 1 --> x ends in 3 --> 9x ends in 7)
(6) 78,736 < 7x < 79,996  (from 4,5)
(7) 78,771 < 7x < 79,961  (from 3,6)
(8) SEVEN = 78,981 or SEVEN = 79,891 (by scrolling through all
seventeen possible cases of 78,771 + 70n < 79,961 on a
calculator and noting the two cases where E=E)
(9)SEVEN = 78,981 (since 79,891*(9/7)=102,717 NINTHS)
   and NINTHS = 101,547 

 - Matt Sheppeck
 
 
 This is my solution to the SEVEN/NINTHS problem
 by Michael Trigiani
 
 I did this problem by hand with some trial and error.
 
 7x = SEVEN and 9x = NINTHS
 
 I found the lower and upper bound for x.  The upper bound is found by
 98784/7 = 14112 (98784 is the highest possible number SEVEN could be
 divisible by 7).  The lower bound is found by 101259/9 = 11251 (101259 is
 the smallest possible number NINTHS could be divisible by 9).  Therefore the
 range that x could be is 11251-14112.
 
 14112*9 would give the range that NINTHS could be, which is 127008.  This
 tells us that N=1, which also tells us that the ones digit in x is 3, and
 also tells us that S=7
 
 7x = 7EVE1 and 9x = 1I1TH7
 
 I know found a new upper and lower bound for x.  The upper bound is found by
 79891/7 = 11413 (79891 is the highest possible number SEVEN could be
 divisible by 7).  The lower bound is found by 70301/7 = 10043 (70301 is the
 smallest possible number SEVEN could be divisible by 7).  Therefore the
 range that x could be is 10043-11413.
 
 11413*9=102717 which shows that I=0.
 
 7x = 7EVE1 and 9x = 101TH7
 
 Because 1+0+1+7=9, then the sum of T+H must be a multiple of 9.  The only
 possible choices for NINTHS at this point would be (101367, 101457, 101547,
 101637).  Dividing each of these choices by 9 would in the possibilities of
 what x is.  (101367/9=11263, 101457/9=11273, 101547/9=11283, 10163/9=11293).
 
 Using these possibilities for x and multiplying them with 7 will determine
 the value of SEVEN (11263*7=78841, 11273*7=78911, 11283*7=78981,
 11293*7=79051).
 
SEVEN=78981, NINTHS=101547, SEVEN/NINTHS=78981/101547=7/9

 seven/ninths = 78981/101547
 Jeff Smith
 
 Hi Ed,
 
 78981/101547 fits the bill.
 
 Regards,
 
Mike Shafer